Display n-th element in the list

main.c

@@ -14,12 +14,28 @@ void rem(struct List **list, int value_to_remove);
 
 void print_list(const struct List *list);
 
+int *get(const struct List *list, int n);
+
+int llen(const struct List *list);
+
 int main(void) {
     struct List *seznam = init(1);
     add(seznam, 5);
     add(seznam, 2);
     print_list(seznam);
 
+    constexpr int n = 2;
+    int *get_n = get(seznam, n);
+    printf("Attempting to find %d. element => ", n);
+    if (get_n == NULL) {
+        // element doesn't exist
+        printf("failed!");
+    } else {
+        printf("succeeded. Value = %d", *get_n);
+        free(get_n);
+    }
+    printf("\n\n");
+
     rem(&seznam, 1);
     print_list(seznam);
 
@@ -102,3 +118,27 @@ void print_list(const struct List *list) {
     }
     printf("\n");
 }
+
+// we will pretend the user is not a programmer and enters n=1 for first element and so on
+int *get(const struct List *list, const int n) {
+    const int list_len = llen(list);
+    if (n > list_len || n <= 0) return nullptr;
+
+    for (int i = 0; i < n - 1; i++) {
+        list = list->next;
+    }
+
+    int *val = malloc(sizeof(int));
+    *val = list->value;
+    return val;
+}
+
+int llen(const struct List *list) {
+    int len = 0;
+
+    for (; list != NULL; list = list->next) {
+        len++;
+    }
+
+    return len;
+}